SpletThe line `lx+my+n=0` is a normal to the parabola `y^2 = 4ax` if. 4,004 views. Oct 11, 2024. 43 Dislike Share Save. Doubtnut. 2.09M subscribers. To ask Unlimited Maths doubts … Splet28. mar. 2024 · the line is : lx + my + n = 0 .....(ii) The centre of the circle (i) is at (0, 0) and radius is r units. Since the line (ii) touches the circle (i), the radius of the circle and the …

The line lx + my + n = 0 is a normal to the ellipse x^2a^2 + y^2b^2 = 1 if

SpletIf the lines lx+my+n =0, mx+ny+l= 0 and nx+ly+m = 0 are concurrent then ( l,m,n≠0) A l+m+n=0 B l−m−n=0 C l+m−n=0 D m+n−l=0 Solution The correct option is A l+m+n=0 Since the lines are concurrent, so ∣∣ ∣ ∣ l m n m n l n l n∣∣ ∣ ∣= 0 ⇒ 3lmn−l3−m3−n3 =0 ⇒ (l+m+n)(l2+m2+n2−lm−mn−nl)= 0 ⇒ (l+m+n)1 2((l−m)2+(m−n)2+(n−l)2)= 0 ⇒ l+m+n= 0 SpletThree lines lx + my + n = 0, mx + ny + l = 0, nx + ly + m = 0 are concurrent. So, that means those three lines meet at a common point and l m n m n l n l m = 0. Thus, l ( mn - l 2) - m ( … success with disabilities program

[Solved] Find the condition that the line $lx+my+n=0$ is

SpletIf the straight line l x + m y + n = 0 is normal to the ellipse a 2 x 2 + b 2 y 2 = 1 then prove that: l 2 a 2 + m 2 b 2 = n 2 (a 2 − b 2) 2 SpletThe line `lx + my + n = 0` is a normal to `(x^(2))/(a^(2)) + (y^(2))/(b^(2)) =1`, provided success with one jump