Cannot convert from string to url in swift 3
Webinit(fileURLWithPath: String) Initializes a newly created NSURL referencing the local file or directory at path. class func fileURL(withPathComponents: [String]) -> URL? Initializes and returns a newly created NSURL object as a file URL with specified path components. init(resolvingAliasFileAt: URL, options: NSURL.BookmarkResolutionOptions) WebJan 28, 2024 · Cannot convert value of type 'String' to expected argument type 'URLSession' Ask Question Asked 4 years, 2 months ago Modified 4 years, 2 months ago Viewed 2k times 0 I use Alamofire 4.0, Swift 4.2 and Xcode 10.2 to request Http Api I have url constant: let weatherUrl = "http://api.openweathermap.org/data/2.5/weather" And …
Cannot convert from string to url in swift 3
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WebMay 28, 2024 · If you want to get the best conversion possible, you need to use Foundation’s StringTransform type then call applyingTransform () on your string. You … WebNov 1, 2016 · This way you don't need to convert a path to an URL, because you're using an URL from the beginning, and you can handle errors. In your specific case, you will know if your asset is there and if your URL is correct. Share Improve this answer Follow edited Nov 1, 2016 at 15:01 answered Nov 1, 2016 at 14:55 Eric Aya 69.2k 35 179 250 Add a …
WebMar 28, 2024 · Use the String method addingPercentEncoding (withAllowedCharacters:) to URL encode a string directly: var decoded = "url components" var encoded = decoded.addingPercentEncoding( withAllowedCharacters: .urlQueryAllowed ) // encoded is "url%20components" URL Property Examples URLs and Strings WebMar 22, 2024 · 1 Answer Sorted by: 0 When you return in a closure, you are not returning the function getMachineName, you are returning the closure itself. Note that the closure is defined to have type ( [MachineDetails]? , Error?) -> Void, meaning once it is called, you won't be returning in the closure.
WebJun 19, 2024 · It appears that your getScreenShotDirectory () method is already a URL. So you get the error trying to pass a URL to the URL (string:) method which, of course, expects a String, not a URL. The simple solution is to properly convert the URL to a path string: let pathURL = getScreenShotDirectory () // URL let pathString = pathURL.path // String Share WebAnd I try to convert Data to String in this line: returnData = String (data: dataVar, encoding: .utf8) Swift compiler gives me an error, and change this line to returnData = String (data: dataVar, encoding: .utf8)! , when I execute this line I get empty returnData variable. If I use basic example line print (String (data: data, encoding: .utf8 ...
WebSep 29, 2014 · The reason why you can't do that is because String doesn't have an initializer accepting a double or a float, whereas it implements initializers for all integer types (Int, Uint, Int32, etc.). So @derdida's solution is the right way to do it. I discourage using the description property.
WebMay 3, 2024 · results in error: cannot convert value of type 'String' to expected argument type 'Character' I also tried creating a character variable var selectedChar:Character = selectedLetter but I get a conversion error: error: cannot convert value of type 'String?' to specified type 'Character' curd fermentationWebDec 1, 2024 · 3 to convert url to string use this var myurl: NSURL var urlString: String = myurl.absoluteString hope it helps Share Improve this answer Follow answered Dec 3, 2024 at 12:05 Wassim Ben Hssen 509 6 22 I have to modify to urlString = (strurl as AnyObject).absoluteString! – Antonio Abrantes Dec 6, 2024 at 1:20 Add a comment 3 curd fest madisonWebJul 23, 2024 · You need to call the Instance Property absoluteString in order to retrieve the URL string. Change self.sendDatatoDatabase (photoUrl: url) to guard let url = url else {return} self.sendDatatoDatabase (photoUrl: url.absoluteString) it will make you avoid to force unwrap Share Improve this answer Follow answered Jul 24, 2024 at 4:41 Soren … easy elizabethan recipes